I’m writing in
e) All or none of the above.
The struggle is real
a == d
a + d = b
c = burn it down
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Godel showed that self-referential problems like this are impossible to resolve. He proved that the existence of these types of problems mean that math can never completely describe reality as outlined in his incompleteness theorems -> https://en.wikipedia.org/wiki/Gödel’s_incompleteness_theorems
This is one of the drivers of post-modernist thinking. Douglas Hofstadter talks a lot about this and the nature of consciousness in his famous book Gödel, Escher, Bach -> https://en.wikipedia.org/wiki/Gödel%2C_Escher%2C_Bach
as far as i understand, godel’s incompleteness doesn’t touch reality or ability for math to describe reality. math is very vast and we only need a fraction of it to describe reality right now. whether this description is correct is debatable but not part of godel’s proof, which to me only means math can’t be “summarized” into a set of “universal” rules. i may be wrong tho, godel’s work is a lot to take in
Yes, I described it badly and that description is inaccurate. It is technically about completeness which has a very specific definition. The implication that no formal logic system could describe even itself fully and that was a major blow to modernist “clock-maker’s universe” view of the reality.
Classical paradox question. There is no correct answer.
Oh fuck.
33.3333333333333333333333333333333…
The answer is 50% without it being b). There is also test optimization strategy for answering F’d up questions. If 2 options are the same, they can not be intended answer of test maker.
depending on the rules
Ah fuck, there goes my right to vote in Jim Crow South.
Help, my mind is caught in a paradoxical loop!
have you tried turning it off and on again?
Its askimg for a subscription now…
I try not to day drink
It’s always nighttime somewhere
I’ve had a bit of a tumble.
Cave Johnson prevails again!
Chance == odds
so 4/4 == totalChoice_permitted one_Choice = 1/4 A=25 B=50 C=0 D=25 if one_Choice == one_Choice then combine reduce choices by the amount simlair plus one A==D combine 3/3 == totalChoice_permitted one_Choice = 1/3 turn to decimal (one_Choice) x 100 == 33% 1 = AD =25% 2 = B =50% 3 = C =0% if answer not equal to (one_Choice) print “the answer is not listed but the answer is in the struggle of answering a question so 0%”Not C but 0% Not all odds matter or they do. It’s a double whammy
or do I got pie on my face?
Is it the percentage or the place holder?
What are the rules?
I would think it would be safe to assume the limits are out of four choices but when two are the same.
like linear or some shit.
Update: I asked my local AI clown clanker and it gave this as a answer
A clever question! Since the answer is chosen at random, each option has an equal chance of being correct. Therefore, the probability that I will be correct if I pick randomly is: 1/4 = 25% So, the correct answer is (a) 25%!
The olgipity is very sure of A) and not D)
So if you are playing Russian roulette with 5 loaded chambers, you can ignore 4 of them because the outcome is the same as one of the other chambers, meaning you have a 50/50 chance of winning. Truly astounding math.
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If you were to pick at random it would be 25% given there are 4 options being. However, that isn’t the same as the question about the question, which you see 25% percent twice meaning you could Be randomly right twice actually, so the answer to this question about a question is b.) 50%.
No, because if you choose randomly there’s only a 25% chance of choosing B.
But if your answer is 25% there is a 50% chance of randomly getiing it right.
G.E.B.
